# Two Trains of Equal Lengths Take 10 Seconds and 15 Seconds Respectively to Cross a Telegraph Post. If the Length of Each Train be 120 Meters, in What Time, (in Seconds) Will They Cross Each Other Travelling in Opposite Direction?

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 5

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## Explanation

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. As, length is given (120m) so individual speeds of both trains will be calculated by the speed distance formula.

In the next step, relative speed would be determined, by adding their speeds because both are moving in opposite direction. And finally,

Time = Distance/Speed

Time = ?

## Solution

Speed of first train = 120/10 = 10 m/sec

Speed of second train = 120/15 = 8 m/sec

Relative speed = 12 + 8 = 20 m/sec

Total length = 120 + 120 = 240m

Now,

Time = distance/speed

Time = 240/20

### Conclusion

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 meters, then in 12 seconds they will cross each other travelling in opposite direction.

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 7

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