# Two Trains of Equal Length are Running on Parallel Lines in the Same Direction at 46 km/h and 36 km/hr. The Faster Train Passes the Slower Train in 36 Seconds. The Length of Each Train is?

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 5

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## Explanation

Two trains of equal length are running on parallel lines in the same direction so average velocity will be calculated by subtracting 36 from 46 km/h.

To calculate the length (supposing y, then total length = y + y = 2y) we can use speed distance time formula;

Length (distance) = speed x time

## To Find

Length of the train = ?

## Solution

Relative speed = 46 – 36 = 10 km/h

This speed in m/sec will be;

Relative speed = (10 x 1000)/3600 = 25/9 m/sec

As, there are two trains, so total length = y + y = 2y (Let suppose length of train is “y”)

Now,

length = speed x time

2y = (25 x 36)/9

2y = 100

### Conclusion

Two trains of equal length are running on parallel lines in the same direction at 46 km/h and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train will be 50m.

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 7

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