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# A Train Takes 18 Seconds to Pass Completely Through a Station 162 Meter Long and 15 Seconds Through Another Station 120 meter Long. The Length of the Train is?

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 4

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## Explanation

There are two trains.

• Train A takes 18 seconds to pass completely through a station 162m long.
• Train B takes 15 seconds to pass completely through a station 120m long.
• Both trains have equal length.

Let suppose the length of the train is “g”.

For train A;

Total length = g + 162

For train B;

Total length = g + 120

Now, by using the speed distance formula we can make two different equations and then length can be find-out easily by solving or equating the equations.

## To Find

Length of the train = ?

## Solution

As, we know that

Distance = Speed x Time

For train A

Speed = Distance/Time

Speed = (g + 162)/18 __________ (i)

Total length = length of train + length of platform

For train B

Speed = distance/time

Speed = (g + 120)/15 __________ (ii)

Total length = length of train + length of platform

As the left hand sides of the equation (i) and (ii) are same, so their right hand sides should be same.

(g + 162)/18 = (g + 120)/15

15g + 2430 = 18g + 2160

18g – 15g = 2430 – 2160

3g = 270

g = 270/3

### Conclusion

So if a train takes 18 seconds to pass completely through a station 162 meter long and 15 seconds through another station 120 meter long. The length of the train will be 90m.

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 6

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