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If the sum of one-half and one fifth of a number exceeds one third of that number by 7 1/3, the number is?

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Explanation

  • If the sum of one-half and one fifth of a number.
  • Exceeds one third of that number by 7 1/3 (22/3).

The number can be figure out in this way.

Let suppose the number is y.

Sum of one-half and one-fifth of y.

y/2 + y/5

“y/2 + y/5” exceeds one-third of y by 7 1/3 (22/3).

y/2 + y/5 – 22/3 = y/3 ________ (i)

Through this equation we can easily figure out the value of y (y = 20).

To Find

Number = ?

Solution

Let suppose

Number = y

According to the given condition

y/2 + y/5 – 22/3 = y/3

y/2 + y/5 – y/3 = 22/3

3(15y + 6y – 10y) = 22 x 30

33y = 660

y = 20

Required Number = 20 answer

Conclusion

If the sum of one-half and one fifth of a number exceeds one third of that number by 7 1/3 (22/3), the number is 20.

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