- If 7 spiders make 7 webs in 7 days.

- Days required by one spider to make one web will be figure out in this way.

## Explanation

Three given entities here are

- Spiders
- Web
- Days

To determine the relation here, let suppose; Days required by one spider to make one web = y

__Case I__

Spiders Days

7 7

1 y

- Seven spiders requires less days.
- One spider will require more days.

This clearly indicates that there is inverse relation.

Direct/Indirect relation tells how the equation will be written.

1 : 7 :: 7 : y ________ (i)

__Case II__

Web Days

7 7

1 y

- 7 (seven) web requires more days.
- 1 (one) web would require less days.

This clearly indicates that there is direct relation.

Direct/Indirect relation tells how the equation will be written.

7 : 1 :: 7 : y ________ (ii)

By (i) and (ii)

1 : 7 :: 7 : y

7 : 1

7 x 1 x 7 = 7 x 1 x y ________ (A)

After simplifying equation (A), we can easily figure out the value of y (y = 7)

## To Find

Days required by one spider to make one web = ?

## Solution

__Method I__

Let suppose

Days required by one spider to make one web = y

Spider Web Days

7 7 7

1 1 y

- Relation between spider and days is inverse.
- Relation between web and days is direct so;

1 : 7 :: 7 : y

7 : 1

7 x 1 x 7 = 7 x 1 x y

49 x 1 = 7y

7y = 49

y = 49/7

y = 7 days

**Days required by one spider to make one web**** = 7 days answer**

__Method II__

Days required by 7 spiders to make 7 web = 7 days

Days required by 7 spiders to make 1 web = 7/7 days

Days required by 7 spiders to make 1 web = 1 day

Days required by 1 spider to make 1 web = 1 x 7 days

Days required by 1 spider to make 1 web = 7 days

**Days required by one spider to make one web**** = 7 days answer**

### Conclusion

If 7 spiders make 7 webs in 7 days then one spider will make one web in 7 days.