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How Many Tiles of 20cm2 will be Required to have a Footpath 1m Wide Carried Around the Outside of Grassy Plot 24m Long and 14m Broad?

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AKIF HAMEED

AUTHOR

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Table of Contents – How Many Tiles of 20cm2 will be Required?

  • How many tiles of 20cm2 will be required?
  • To have a footpath 1m wide.
  • Carried around the outside of grassy plot 24m long and 14m broad.
  • The required number of tiles can be figure out and has figured out in the solution below.

Note: This question was asked in Competitive Examination (CSS) – 2021 General Science & Ability Q6 (B).

Important Points To Solve The Problem

Following things are needed to discuss here.

  • Area required to be paved.
  • Area of tile.
  • Number of tiles.

Following things are given.

  1. Size of a tile (20cm2).
  2. Dimension of grassy plot (24m long and 14m broad).
  3. Extension in footpath (1m wide).

First, we will calculate the area (in centimeters) required to be paved and then dividing it with the area of a tile (20cm2) we can easily figure out the total number of tiles.

To Find

Number of tiles = ?

Solution

40000 tiles of 20cm2 will be required to have a footpath 1m wide carried around the outside of grassy plot 24 meter long and 14 meter broad.
40000 tiles of 20cm2 will be required to have a footpath 1m wide carried around the outside of grassy plot 24 meter long and 14 meter broad.

First Method

It is clear from the picture that we have four rectangles whose area in square centimeter is required to calculate.

Case I

Area of first rectangle = 26m x 1m

Area of first rectangle = 26m2

Area of first rectangle in square centimeters = (26 x 100 x 100) cm2

Area of first rectangle in square centimeters = 260000 cm2

Case II

Area of second rectangle = 26m x 1m

Area of second rectangle = 26m2

Area of second rectangle in square centimeters = (26 x 100 x 100) cm2

Area of second rectangle in square centimeters = 260000 cm2

Case III

Area of third rectangle = 14m x 1m

Area of third rectangle = 14m2

Area of third rectangle in square centimeters = (14 x 100 x 100) cm2

Area of third rectangle in square centimeters = 140000 cm2

Case IV

Area of fourth rectangle = 14m x 1m

Area of fourth rectangle = 14m2

Area of fourth rectangle in square centimeters = (14 x 100 x 100) cm2

Area of fourth rectangle in square centimeters = 140000 cm2

Now;

Total area = (260000 + 260000 + 140000 + 140000) cm2

Total area = 800000 cm2

Size of a tile = 20 cm2

Area of one tile = 20cm x 20cm = 400 cm2

Number of tiles = 800000/400

Number of tiles = 2000 answer

Second Method

Total area of grassy plot including footpath = 26 x 16

Total area of grassy plot including footpath = 416 m2

Area of grassy plot excluding footpath = 24 x 14

Area of grassy plot excluding footpath = 336 m2

Area of footpath = 416 – 336

Area of footpath = 80 m2

Area of footpath in centimeters = (80 x 100 x 100) cm2

Area of footpath in centimeters = 800000 cm2

Size of a tile = 20 cm2

Area of one tile = 20cm x 20cm = 400 cm2

Number of tiles = 800000/400

Number of tiles = 2000 answer

Conclusion

40000 tiles of 20cm2 will be required to have a footpath 1m wide carried around the outside of grassy plot 24m long and 14m broad.

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2 COMMENTS

  1. i think you have done mistake. it’s not size of tile dividing the area of footpath. it should be area of tile (20*20=400) dividing the area of foot path. it should not be 800000/20 rather it should be 800000/400=2000. So here answer should be 2000 tites are required to cover the area of footpath which is 80meters square or 800000cm square.

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