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Animals that farmer keeps
As it is quite obvious that each animal has 1 head but legs are not same. Each hen has 2 legs and each rabbit has 4 legs.
We are provided with the total number of heads i.e. 70. It means h + r = 70 and total number of legs are 196 i.e. 2h + 4r = 196.
Now we have 2 equations and by solving them simultaneously we can find out the required answer.
How many more hens than rabbits does the farmer have = ?
h shows the hens and r shows the rabbits
So, total number of heads
h + r = 70 ___________ (i)
As, each hen has 2 legs so h hen will have 2h legs and each rabbit has 4 legs so r rabbit will have 4r legs.
So total number of legs
2h + 4r = 196 (Dividing the both sides of the equation with 2)
h + 2r = 98 __________ (ii)
Subtracting (i) from (ii)
(h + 2r) – (h + r ) = 98 – 70
h + 2r – h – r = 28
r = 28
Put r = 28 in equation (i)
h + 28 = 70
h = 70 – 28
h = 42
h – r = 42 – 28 = 14 hens
A farmer keeps hens and rabbits on his farm. One day, he counted a total of 70 heads and 196 legs. There would be 14 hens more than rabbits that he have.