- An industrial loom weaves 0.128 m of cloth every second.

- The time required for the loom to weave 25 m of cloth can be figure out in this way.

## Explanation

Two given entities here are

- Cloth
- Time

To determine the relation here, let suppose; the time required for the loom to weave 25 m of cloth = y

__Case__

As we know that;

Cloth Time

0.128 m 1 sec

25 m y

- More time means more cloth (Loom can weave too much cloth).
- Less time means less cloth.

This clearly indicates that there is direct relation.

Direct/Indirect relation tells how the equation will be written.

0.128 : 25 :: 1 : y ________ (A)

After simplifying equation (A), we can easily figure out the value of y (y = 195 sec )

## To Find

The time required for the loom to weave 25 m of cloth = y

## Solution

__Method I__

Let suppose

The time required for the loom to weave 25 m of cloth = y

Cloth Time

0.128 m 1 sec

25 m y

Relation between cloth and time is direct, so;

0.128 : 25 :: 1 : y

0.128 x y = 1 x 25

0.128y = 25

y = 25/0.128

y = 195.32 sec

**T****he approximate time required for the loom to weave 25 m of cloth**** = 195 sec answer**

__Method II__

0.128 m of cloth requires time = 1 sec

1m of cloth requires time = 1 / 0.128

1m of cloth requires time = 7.8 sec

25m of cloth requires time = 7.8 x 25

25m of cloth requires time = 195.32 sec

**T****he approximate time required for the loom to weave 25 m of cloth**** = 195 sec answer**

## Conclusion

An industrial loom weaves 0.128 m of cloth every second. Approximately, 25 m of cloth can be weaved in 195 seconds.