# A Train 108 Meter Long Moving at a Speed of 50 km/h Crosses a Train 112 Meter Long Coming from Opposite Direction in 6 Seconds. The Speed of the Second Train is?

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 5

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## Explanation

• A train 108 meter long moving at a speed of 50 km/h crosses another train which is coming from opposite direction.

As, both trains are moving in opposite direction so their average speed will be determined by adding.

Taking the total distance 108 + 112 = 220 meter, the speed of other train can be find out easily.

Speed = Distance/Time

Speed = ?

## Solution

Given speed = 50 km/h

Now, in m/sec

Given speed = (50 x 1000)/3600 = 125/9 m/sec

Let the required speed = y

So,

Relative speed = 125/9 + y

Total length = 108 + 112 = 220 meter

Speed = distance/time

125/9 + y = 220/6

y = 220/6 â€“ 125/9

y = (660 â€“ 250)/18

y = 410/18

y = 205/9 m/sec

y = 22.778 m/sec

And in km/h

y = (22.778 x 3600)/1000

### Conclusion

A train 108 meter long moving at a speed of 50 km/h crosses a train 112 meter long coming from opposite direction in 6 seconds. The speed of the second train will be 82 km/h.

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 7

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